(x+2)^2-(x-2)^2=3(3x-2)-15

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Solution for (x+2)^2-(x-2)^2=3(3x-2)-15 equation: 



(x+2)^2-(x-2)^2=3(3x-2)-15

We move all terms to the left:

(x+2)^2-(x-2)^2-(3(3x-2)-15)=0



We calculate terms in parentheses: -(3(3x-2)-15), so:

3(3x-2)-15

We multiply parentheses

9x-6-15

We add all the numbers together, and all the variables

9x-21

Back to the equation:

-(9x-21)



We get rid of parentheses

(x+2)^2-(x-2)^2-9x+21=0

We add all the numbers together, and all the variables

-9x+(x+2)^2-(x-2)^2+21=0

We move all terms containing x to the left, all other terms to the right

-9x+(x+2)^2-(x-2)^2=-21

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